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  • A capacitor of capacitance is charged by a 100 V battery. The capacitor is disconnected from th

A capacitor of capacitance 900\; \mu F is charged by a 100 V battery. The capacitor is disconnected from the battery and connected to another uncharged identical capacitor such that one plate of uncharged capacitor is connected to the positive plate and another plate of uncharged capacitor is connected to the negative plate of the charged capacitor. The loss of energy in this process is measured as x \times 10^{-2}J the value of x is

 

Option: 1

225


Option: 2

__


Option: 3

__


Option: 4

__


Answers (1)

best_answer

\begin{aligned} & Q=900 \times 100 \mu \mathrm{C} \\ & Q=9 \times 10^{-2} \mathrm{C} \end{aligned} ------------------(I)

Now,

\begin{aligned} & \Delta U=\frac{1}{2} \frac{C_1 \cdot C_2}{C_1+C_2}\left(V_1-V_2\right)^2 \\ & =\frac{1}{2} \times \frac{C \times C}{2 C} \times(100-0)^2 \end{aligned}

=\frac{C}{4}\times 100\times100

=\frac{900}{4}\times 10^{-6}\times100^{-4}

=\frac{9}{4}=2.25 J=\frac{9}{4}=2.25 J

\Delta U=225\times 10^{-2}J

 

Posted by

Deependra Verma

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