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  • A car is moving with the speed of 30m/s on a cirular path of 300m. Its speed is increasing at the rate of 4m/s2. What is the accerleration (in m/s2) of the car? <p

A car is moving with the speed of 30m/s on a cirular path of 300m. Its speed is increasing at the rate of 4m/s2. What is the accerleration (in m/s2) of the car?

 

Option: 1

5


Option: 2

4


Option: 3

3


Option: 4

10


Answers (1)

best_answer

 

 

Force in non-uniform Circular Motion -

F_{c}=ma_{c}=\frac{mv^{2}}{r}             (\vec{F}_{c} \perp \vec{v})

Ft = mat

F_{net}=m\sqrt{a_{c}^{2}+a_{t}^{2}}

m = mass

ac= centripetal acceleration

at = tangential acceleration

Fc = centripetal force

-

 So

 a_{c}= \frac{v^{2}}{R} = \frac{30*30}{300} = 3m/s^{2}

a_{T}= 4m/s^{2}

a = \sqrt{a_{c}^{2}+a_{T}^{2}} = \sqrt{3^{2}+4^{2}} = 5m/s^{2}

 

 

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