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A car moves at a constant speed of   10\ \frac{m}{s}  on a circular horizontal track with a radius of 10 m. A ball is suspended from the roof of the car by a light and strong rod. The rod makes an angle with the track  g=10 \, {m}/{s^2}

Option: 1

 Zero


Option: 2

 30°


Option: 3

 45°

 


Option: 4

 60°


Answers (1)

best_answer

By centrifugal force formula:

 Tsin\theta=\frac{mv^2}{R}

Where, M = tangential velocity and r = circular path radius

 Tcos\theta\ =\ mg

Therefore,

 tan\theta\ =\ \frac{v^2}{Rg}

Or,              tan\theta\ =\ \frac{\left(10\right)^2}{10\times10}

Or,                    tan\theta\ =45^{\circ}     

Posted by

Kuldeep Maurya

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