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A car moving with a speed of 50 km/hr, can be stopped by brakes after at least 6 m. If the same car is moving at a speed of 100 km/hr, the minimum stopping distance is

Option: 1

12 m


Option: 2

18 m


Option: 3

24 m


Option: 4

6 m


Answers (1)

best_answer

:         For first case,

                    u_{1}= 50\frac{km}{hour}= \frac{50\times 1000}{60\times 60}= \frac{125}{9}\frac{m}{sec}

\therefore         Acceleration

                    a= -\frac{u_{1}^{2}}{2s_{1}}= -\left ( \frac{125}{9} \right )^{2}\times \frac{1}{2\times 6}= -16\: m/sec^{2}

        For second case

                    u_{2}=100\, \; \frac{km}{hour}=\frac{100\times 1000}{60\times 60}=\frac{250}{9}\frac{m}{sec}

\therefore \; s_{2}=\frac{-u_{2}^{2}}{2a}=\frac{-1}{2}\left ( \frac{250}{9} \right )^{2}\times \left ( -\frac{1}{16} \right )=24m  

or      s_{2}=24m

Posted by

Irshad Anwar

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