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  • a car starting from rest accelerates at the rate f through a distance s then continues at constant speed for same time t and the

a car starting from rest accelerates at the rate f through a distance s then continues at constant speed for same time t and then deccelerates at the rate f/2 to come to rest.If the totl distance is 5s then prove that s=1/2 f t^2

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car starting from rest accelerates at the rate f through a distance s then continues at constant speed for same time t and then deccelerates at the rate f/2 to come to rest.If the totl distance is 5s then prove that s=1/2 f t^2

Answer:

Solution is in attachment 

for the last step 

total\ distance\\5s=s_{1-2}+s_{2-3}+s_{3-4}\\5s=s+ft^2+ft^2\\so, \ s=\frac{1}{2}ft^2

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