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  •  A Carnot  engine absorbs 1000 J of heat energy from a reservoir at 1270C and rejects 600 J of heat energy during each cycle. The   efficiency of engine and temperatu

 A Carnot  engine absorbs 1000 J of heat energy from a reservoir at 1270C and rejects 600 J of heat energy during each cycle. The   efficiency of engine and temperature of  sink will be :            

 

Option: 1

20% and - 430C


Option: 2

40% and - 330C


Option: 3

50% and - 200C


Option: 4

70% and - 100C


Answers (1)

best_answer

As learnt  

Efficiency of carrot engine is \eta =\frac{Q_{1}-Q_{2}}{Q_{1}}= 1-\frac{T_{2}}{T_{1}} ----------------------- (1)

\\ \\ Q_{1}=1000 J \\ \\ Q_{2}=600 J \\ \\ T_{1}=(273+127)K = 400K

\therefore \eta =1 - \frac{600}{1000}=0.4

\Rightarrow 0.4=1- \frac{T_{2}}{400} \: \: \: or \: \: \: \frac{T_{2}}{400}=0.6

or \: \: \: T_{2}=240K = \: -33^{\circ}C

Posted by

Anam Khan

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