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  • A cell, shunted by a resistance, is balanced across a potentiometer wire of length <img

A cell, shunted by a \mathrm{8\Omega} resistance, is balanced across a potentiometer wire of length \mathrm{3m}. The balancing length is \mathrm{2m} when the cell is shunted by \mathrm{4\Omega} resistance. The value of internal resistance of the cell will be _______\mathrm{\Omega}.

Option: 1

8


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{\frac{\varepsilon}{R+r} \times R=K } l\\

In the first case           

\mathrm{\frac{\varepsilon}{8+r} \times 8=K \times 3}         .................(1)

In the second case

\mathrm{\frac{\varepsilon}{4+r} \times 4=K\times2}            .................(2)

Solve (1) and (2)

\mathrm{r=8\Omega}

Hence the answer is \mathrm{8\Omega}

Posted by

Anam Khan

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