Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A certain charge Q is divided into two parts q and (Q–q). How should the charges Q and q be divided so that q and (Q–q) placed at a certain distance apart experience maximum electrostatic repulsion ?  Option: 1 <img alt

A certain charge Q is divided into two parts q and (Q–q). How should the charges Q and q be divided so that q and (Q–q) placed at a certain distance apart experience maximum electrostatic repulsion ?
 
Option: 1 Q=\frac{q}{2}
Option: 2 Q=2 q
Option: 3 Q=4 q
Option: 4 Q=3 q

Answers (1)

best_answer

\\\text{Electrostatic Force of} =F=\frac{k q_{1} q_{2}}{r^{2}} \; \text{repulsion}\\ F=\frac{k q(Q-q)}{r^{2}}

For maximum force,

\begin{aligned} \frac{d F}{d q} &=O \\ F &=\frac{k\left(Qq-q^{2}\right)}{r^{2}} \\ \frac{d F}{d q} &=\frac{k}{r^{2}}\left[\frac{d}{d q}(Q q)-\frac{d}{d q}\left(q^{2}\right)\right] \end{aligned}

\begin{gathered} 0=Q \times 1-2 q \\ \Rightarrow q=\frac{Q}{2} \end{gathered}

The correct option is (2).

Posted by

vishal kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JAC Chandigarh Counselling 2025: Round 1 seat allotment result out for BTech admissions
anam-khan

JoSAA round 5 seat allotment result 2025 out on josaa.nic.in
anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today

Latest Question