the number of angular nodes are given by ‘l’, i.e., one angular node for p orbitals, two angular nodes for ‘d’ orbitals and so on.
Radial modes = n-l-1
The total number of nodes are given by (n–1), i.e., sum of l angular nodes and (n – l – 1) radial nodes.
Given
A certain orbital has no angular nodes and two radial nodes,
So, l=0 ,
It will be s orbital, it does not have angular nodes.
And
Radial nodes = 2
n – l –1 = 2
n – 0 – 1 = 2
n= 3
So, The orbital will be 3s.
Therefore, the Correct option is (1)
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