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  • A charged particle enters a uniform magnetic field with velocity vector at an angle of 45° with the magnetic field. The pitch of the helical path followed by the particle is p. The radius of th

A charged particle enters a uniform magnetic field with velocity vector at an angle of 45° with the magnetic field. The pitch of the helical path followed by the particle is p. The radius of the helix will be:

Option: 1

\mathrm{\frac{p}{\sqrt{2} \pi}}


Option: 2

\mathrm{\sqrt{2} \mathrm{p}}


Option: 3

\mathrm{\frac{p}{2 \pi}}


Option: 4

\mathrm{\frac{\sqrt{2} p}{\pi}}


Answers (1)

best_answer

\mathrm{p=\frac{v}{\sqrt{2}} \times T, r=\frac{m v / \sqrt{2}}{q B} }
\mathrm{T=\frac{2 \pi m}{q B}}
 

Posted by

rishi.raj

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