Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A charged particle is moving in a circle of radius R. The speed of the particle is constant and it is equal to v. Then current through any cross-section isOption

A charged particle is moving in a circle of radius R. The speed of the particle is constant and it is equal to v. Then current through any cross-section is

Option: 1

I=\frac{qv}{2R}


Option: 2

\frac{qv}{2\pi R}


Option: 3

I=\frac{qR}{2v}


Option: 4

\frac{qv}{R}


Answers (1)

best_answer

Time taken by the charge to complete the circle is T=\frac{2\pi R}{v }\rightarrow (1)

Hence its frequency is f=\frac{1}{T}

                 f=\frac{v }{2\pi R}

current is i=q.f=\frac{qv }{2\pi R}.

 

Posted by

HARSH KANKARIA

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 session 2 answer key out for BArch, BPlanning; response sheet on jeemain.nta.nic.in
anam-khan

JEE Mains 2025 Paper 2 Answer Key LIVE: BArch final answer key PDF expected soon at jeemain.nta.nic.in
anam-khan

JEE Main 2025 response sheet errors: Delhi HC allows student to apply for JEE Adv, seeks NTA explanation

Latest Question