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A chemical reaction proceeds as follows:
\mathrm{A}+\mathrm{C} \longrightarrow \mathrm{D}+\mathrm{F}            (slow)
\mathrm{F}+\mathrm{B} \longrightarrow \mathrm{G}                      (fast)
\mathrm{G}+\mathrm{C} \longrightarrow \mathrm{E}                      (fast)
find the order of reaction?

Option: 1

2


Option: 2

1


Option: 3

0


Option: 4

3


Answers (1)

best_answer

The overall reaction will be -

\mathrm{A+B+2 C \longrightarrow D+E}

The slowest step is the rate-determining step.


\\\mathrm{A+C \longrightarrow D+F \quad \text { (slow) }}\\\\ \mathrm{{\therefore r=k[\mathrm{A}][\mathrm{C}]}} \\\\ \mathrm{\text { Order of reaction }=1+1=2}

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Riya

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