Get Answers to all your Questions

header-bg qa

A circle of radius unity is centred at origin. Two particles start moving at the same time from the point (1,0) and move around the circle in opposite direction. One of the particle moves counterclockwise with constant speed \mathrm{v}and the other moves clockwise with constant speed 3 \mathrm{v}. After leaving (1,0),the two particles meet first at a point \mathrm{P, and continue until they meet next at point \mathrm{Q} .The coordinates of the point \mathrm{Q} are

Option: 1

(1,0)


Option: 2

(0,1)


Option: 3

(0,-1)


Option: 4

(-1,0)


Answers (1)

best_answer

The particle which moves clockwise is moving three times as fast as the particle moving anticlockwise
This tells us that in the time that the clockwise particle travels (3 / 4)^{\text {th }} of
the way around the circle the anticlockwise particle will travel (1 / 4)^{\text {th }} of
the way around the circle and so the 2^{\text {nd }} particle will meet at \mathrm{p}(0,1).
Using the same logic they will meet at Q(-1,0) when they meet the 2 nd time ]

 

Posted by

Ajit Kumar Dubey

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE