Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

A circle \mathrm{\mathrm{C}_2} passes through the centre of the circle \mathrm{\mathrm{C}_1}; \mathrm{x^2+y^2=2} and gets bisected at its point of intersection with \mathrm{\mathrm{C}_1}. The radius of \mathrm{\mathrm{C}_2} is equal to 

 

Option: 1

1 units


Option: 2

2 units


Option: 3

\sqrt{2}


Option: 4

none of these


Answers (1)

best_answer

Let the radius of the circle be r.

Clearly AP=BP=OP=r

\mathrm{\begin{aligned} & \Rightarrow A P^2+O P^2=O A^2=2 \\ & \Rightarrow A P=1 \Rightarrow r=1 \end{aligned}}

 

Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 application correction begins on jeemain.nta.nic.in; edit details by December 2
anam-khan

JEE Mains 2026 LIVE: NTA to conduct session 1 from January 21 to 30; exam pattern, syllabus
anam-khan

JEE Main 2026 correction window opens tomorrow; NTA allows exam city change

Latest Question