Get Answers to all your Questions

header-bg qa

A circular coil of radius r having number of turns n and carrying a current I, produces magnetic field of magnitude B at its centre. B can be doubled by

Option: 1

keeping n unchanged and changing I to  I/2


Option: 2

changing n to n/2  and keeping I unchanged


Option: 3

changing n to 2n and I to 2I


Option: 4

keeping I unchanged and changing n to 2n


Answers (1)

best_answer

The magnetic field at the centre of coil is given by
\mathrm{B=\frac{\mu_0 I n}{2 r} }
Hence the correct choice is (d).

Posted by

SANGALDEEP SINGH

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE