Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A circular copper disc 10 cm in diameter rotates at 1800 rev per minute about an axis through its centre and at right angles to disc. A uniform field of induction B of 1 weber <img alt="\mathr

A circular copper disc 10 cm in diameter rotates at 1800 rev per minute about an axis through its centre and at right angles to disc. A uniform field of induction B of 1 weber \mathrm{m^{-2}} is perpendicular to disc. What potential difference is developed between the axis of the disc and the rim?

Option: 1

0.023 V


Option: 2

0.23 V


Option: 3

23 V


Option: 4

230 V


Answers (1)

best_answer

\mathrm{Here, l=\mathrm{r}=5 \mathrm{~cm}=5 \times 10^{-2} \mathrm{~m}, \omega=2 \pi\left(\frac{1800}{60}\right) \mathrm{rad} / \mathrm{s}}

\mathrm{=60 \pi \mathrm{rad} / \mathrm{s}, \mathrm{B}=1 \mathrm{Wbm}^{-2}}

Posted by

shivangi.bhatnagar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

NTA Exam Calendar 2025 Live: JEE Main, NEET, CUET schedule to be announced soon; download at nta.ac.in
anam-khan

NTA Exam Calendar 2025: JEE Main, NEET, CUET exam dates soon
anam-khan

JEE Main, NEET, CUET 2025 Dates Live: NTA to announce exam calendar soon on nta.ac.in; latest updates

Latest Question