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A circular copper disc 10 cm in diameter rotates at 1800 rev per minute about an axis through its centre and at right angles to disc. A uniform field of induction B of 1 weber \mathrm{m^{-2}} is perpendicular to disc. What potential difference is developed between the axis of the disc and the rim?

Option: 1

0.023 V


Option: 2

0.23 V


Option: 3

23 V


Option: 4

230 V


Answers (1)

best_answer

\mathrm{Here, l=\mathrm{r}=5 \mathrm{~cm}=5 \times 10^{-2} \mathrm{~m}, \omega=2 \pi\left(\frac{1800}{60}\right) \mathrm{rad} / \mathrm{s}}

\mathrm{=60 \pi \mathrm{rad} / \mathrm{s}, \mathrm{B}=1 \mathrm{Wbm}^{-2}}

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shivangi.bhatnagar

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