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A circular plate is rotating horizontal plane, about an axis passing through its center perpendicular to the plate, with an angular velocity \omega. A person sits at the center having two dumbbells in his hands. When he stretches out his hands, the moment of inertia of the system becomes triple. If \mathrm{E} be the initial Kinetic energy of the system, then final Kinetic energy will be \frac{E}{x}. The value of x is

Option: 1

3


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{I}_{1} \omega_{1}=\mathrm{I}_{2} \omega_{2}
\mathrm{I} \omega=3 \mathrm{I} \omega_{2}
\omega_{2}=\frac{\omega}{3}
E=\frac{1}{2} I\omega^{2}
E_{f}=\frac{1}{2} \times 3 \mathrm{I} \times\left(\frac{\omega}{3}\right)^{2}=\frac{\frac{1}{2} \mathrm{I} \omega^{2}}{3}
x=3

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Ritika Harsh

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