Get Answers to all your Questions

header-bg qa

A circular ring of radius r^{^{^{^{^{}}}}} is placed in a homogenous magnetic field perpendicular to the plane of the ring. The field B chnages with time according to the equation B=k t, where is k a constant and t is the time. The electric field in the ring is

Option: 1

\frac{k r}{4}


Option: 2

\frac{k r}{3}


Option: 3

\frac{k r}{2}


Option: 4

\frac{k}{2 r}


Answers (1)

best_answer

\mathrm{\begin{aligned} & \oint \overrightarrow{\mathbf{E}} \cdot \overrightarrow{\mathbf{d} \mathbf{l}}=-\frac{d \phi B}{d t} \\ & \text { or } E \times 2 \pi r=\frac{d}{d t}\left(K t \times \pi r^2\right)=K \pi r^2 \\ & \text { or } E=\frac{K r}{2} \end{aligned}}

Posted by

vishal kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE