A closed organ pipe has length ‘l'. The air in it is vibrating in 3rd overtone with maximum amplitude 'a'. Find the amplitude at a distance of l /7 from the closed end of the pipe.
a
As we have learnt in
The frequency in closed organ pipe -
- wherein
velocity of sound wave
length of pipe
number of overtones
The figure shows variation of displacement of particles in a closed organ pipe for 3rd overtone.
For third overtone
Hence the amplitude at P at a distance from closed end is ‘a’ because there is an antinode at that point
Alternate
Because there is node at x = 0 the displacement amplitude as function of x can be written as
For third overtone
at
Study 40% syllabus and score up to 100% marks in JEE