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A closely wounded circular coil of radius 5 \mathrm{~cm} produces a magnetic field of 37.68 \times 10^{-4} \mathrm{~T} at its center. The current through the coil is _____________A. [Given, number of turns in the coil is 100 and \pi=3.14 ]

Option: 1

3


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

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\mathrm{R =5 \mathrm{~cm}=5 \times 10^{-2} \mathrm{~m} }

\mathrm{B =37.68 \times 10^{-4} \mathrm{~T} }

\mathrm{n =100 }

\mathrm{B= \frac{\mu_0 n i}{2R} }

\mathrm{37.68 \times 10^{-4} =\frac{4 \pi \times 10^{-7} \times 100 \times i}{2 \times 5 \times 10^{-2}} }

\mathrm{\frac{376.8 \times 10^{-6}}{4 \pi \times 10^{-5}}=i }

\mathrm{i=3 \mathrm{~A}}

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Rishabh

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