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  • A coil having N turns is wound tightly in the form of a spiral with inner and outer radii a and b respectively. When a current I pass through the coil, the magnetic field at its centre is:<div

A coil having N turns is wound tightly in the form of a spiral with inner and outer radii a and b respectively. When a current I pass through the coil, the magnetic field at its centre is:

Option: 1

\frac{\mu_0 \mathrm{NI}}{\mathrm{b}}


Option: 2

\frac{2 \mu_0 \mathrm{NI}}{\mathrm{a}}


Option: 3

\mathrm{\frac{\mu_0 N I}{2(b-a)} \log _e \frac{b}{a}}


Option: 4

\mathrm{\frac{\mu_0 I N}{(b-a)} \log _e \frac{a}{b}}


Answers (1)

best_answer

Integrating  d B  from a to  b   \mathrm{d B=\frac{\mu_0 d N I}{2 r}}.

Posted by

Anam Khan

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