A concentration cell is constructed using two electrodes. The initial concentration of
in the anode compartment is
and that in the cathode compartment is
The cell is allowed to come to equilibrium. Calculate the cell potential at
Given,
0.020 V
0.060 V
0.080 V
0.100 V
The overall reaction in the cell can be represented as:
The cell reaction is :
The Nernst equation for the cell can be written as:
where cell is the standard cell potential,
is the gas constant,
is the temperature in kelvins,
is the number of electrons transferred in the cell reaction,
is the Faraday constant, and
is the reaction quotient.
Since the cell is at equilibrium, (the equilibrium constant) and
Using the equation
and solving for
, we get:
The equilibrium constant for the cell reaction can be calculated as:
At equilibrium,
Substituting the values in the equation for , we get:
Solving for E, we get E = 0.080 V.
Study 40% syllabus and score up to 100% marks in JEE
5 g of Na2SO4 was dissolved in x g of H2O. The change in freezing point was found to be 3.820C. If Na2SO4 is 81.5% ionised, the value of x (K
A capacitor is made of two square plates each of side 'a' making a very small angle
A solution of m-chloroaniline, m-chlorophenol and m-chlorobenzoic acid in ethyl acetate was extracted initially with a saturated solution of NaHCO3 to give fraction A. The leftover organic phase was extracted with d