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A constant magnetic field of 1 \mathrm{~T} is applied in the x>0 region. A metallic circular ring of radius 1 \mathrm{~m} is moving with a constant velocity of 1 \mathrm{~m} / \mathrm{s} along the x-axis , At t=0 \mathrm{~s}, the centre \mathrm{O} of the ring is at x=-1 \mathrm{~m}. What will be the value of the induced emf in the ring at t=1 s? (Assume the velocity of the ring does not change.)
Option: 1 2\pi V
Option: 2 2V
Option: 3 0V
Option: 4 1V

Answers (1)

best_answer

At t = 0

At t=1s,

dA= \left ( 2R \right )dx\\

e= \left | \frac{d\phi}{dt} \right |= \left | \frac{d\left ( BA \right )}{dt} \right |\\

   = B\left | \frac{dA}{dt} \right |= B\times 2R\left | \frac{dx}{dt} \right |\\

  = 1\times(2)\times1\\

e= 2V

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vishal kumar

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