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A copper block of mass $\mathrm{5.0kg}$ is heated to a temperature of $\mathrm{500^{\circ}C}$ and is placed on a large ice block. What is the maximum amount of ice that can melt? [ Specific heat of copper : $\mathrm{0.39J g^{-1}}\mathrm{^{\circ}C^{-1}}$ and latent heat of fusion of water : $\mathrm{335}$ $\mathrm{Jg^{-1}}$ ]
Option: 1
$\mathrm{1.5kg}$

Option: 2
$\mathrm{5.8kg}$

Option: 3
$\mathrm{2.9kg}$

Option: 4
$\mathrm{3.8kg}$

Answers (1)

best_answer

$\mathrm{m= 5kg}$

$\mathrm{C_{cu}= 0.39Jg^{-1} {^{\circ}C^{-1}}}$

$\mathrm{L_{water}= 335Jg^{-1}}$

By the principle of calorimeter,

Heat lost by copper =Heat gained by ice

$\mathrm{m_{1} C_{\text {cu }} \Delta T =m_{2} L_{\text {water }}}\\$

$\mathrm{5000 \times 0.39 \times(500-0) =m_{2} \times 335}\\$

$\mathrm{m_{2} =\frac{9.75 \times 10^{5} }{335}g}\\$

$\mathrm{m_{2} =2.9 \mathrm{~kg}}$

Hence the correct answer is option 3

Posted by

shivangi.bhatnagar

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