Get Answers to all your Questions

header-bg qa

A copper rod moves with a constant velocity 'v' parallel to a long straight wire carrying a
current 'I'. Calculate the induced emf in the rod, if the ends of the rod from the wire are at distances 'a' and 'b'.

Option: 1

\frac{\mu_0 \mathrm{iv}}{2 \pi} \cdot \ln \left(\frac{\mathrm{b}}{\mathrm{a}}\right)


Option: 2

\frac{2 \mu_{\mathrm{o}} \mathrm{iv}}{2 \pi} \cdot \ln \left(\frac{\mathrm{b}}{\mathrm{a}}\right)


Option: 3

\frac{\mu_0 \mathrm{iv}}{4 \pi} \cdot \ln \left(\frac{\mathrm{b}}{\mathrm{a}}\right)


Option: 4

\frac{3 \mu_0 \mathrm{iv}}{2 \pi} \cdot \ln \left(\frac{\mathrm{b}}{\mathrm{a}}\right)


Answers (1)

best_answer

\mathrm {\varepsilon=\int \vec{B} \cdot(d \vec{I} \times \vec{V})=\int_a^b \frac{\mu_0 i}{2 \pi x} v d x=\frac{\mu_0 i v}{2 \pi} \cdot \ln \left(\frac{b}{a}\right)}

Posted by

Sayak

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE