# A cricket ball of mass $0.15\; kg$ is thrown vertically up, by a bowling machine, so that it rises to a maximum height of $20\; cm$ after leaving the machine. If the part pushing the ball applies a constant force $F$ on the ball and moves horizontally a distance of  $0.2\; m$ while launching the ball the value of $F$ (is $N$). is $(g=10\; m/s^{2})$ Option: 1 10 Option: 2 100 Option: 3 150 Option: 4 400

Work done by bowling machine = max. P.E. of the ball

$\begin{array}{l} F \times s=m g h \\ F=\frac{m g h}{s}=\frac{0.15 \times 10 \times 20}{0.2}=150 N \end{array}$

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