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  •  A current carrying rectangular loop  is made of uniform wire.The length <img alt="P R=Q S=5 \math

 A current carrying rectangular loop P Q R S is made of uniform wire.The length P R=Q S=5 \mathrm{~cm} and PQ=R S=100 \mathrm{~cm}. If ammeter current reading changes from I to 2I, the ratio of magnetic forces per unit length on the wire P Q due to wire R S  in the two cases respectively \left(f_{P Q}^{I}: f_{P Q}^{2 I}\right) is:  

Option: 1

1: 2


Option: 2

1: 3


Option: 3

1: 4


Option: 4

1: 5


Answers (1)

best_answer

\mathrm{F} \propto \mathrm{I}_{1} \mathrm{I}_{2}

\frac{\mathrm{F}_{1}}{\mathrm{~F}_{21}}=\frac{1}{4}

 

Posted by

Deependra Verma

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