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A current of 10 A exists in a wire of cross sectional area of 5 mm 2 with a drift velocity of 2 \times 10^{-3}ms^{-1}. The number of free electrons in each cubic meter of the wire is _________.
 
Option: 1 1 \times 10^{23}
Option: 2 625 \times 10^{25}
Option: 3 2 \times 10^{25}  
Option: 4 2 \times 10^{6}

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\begin{aligned} &\mathrm{i}=10 \mathrm{~A}, \mathrm{~A}=5 \mathrm{~mm}^{2}=5 \times 10^{-6} \mathrm{~m}^{2}\\ &\text { and } \mathrm{v}_{\mathrm{d}}=2 \times 10^{-3} \mathrm{~m} / \mathrm{s}\\ &\text { We know, i = neAvd }\\ &\therefore 10=\mathrm{n} \times 1.6 \times 10^{-19} \times 5 \times 10^{-6} \times 2 \times 10^{-3}\\ &\Rightarrow \mathrm{n}=0.625 \times 10^{28}=625 \times 10^{25} \end{aligned}

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