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A cylinder of fixed capacity of 44.8 litres contains helium gas at standard temperature and pressure. The amount of heat needed to raise the temperature of gas in the cylinder by 20.0^{\circ} \mathrm{C} will be :
(Given gas constant \mathrm{R}=8.3 \mathrm{JK}^{-1}-\mathrm{mol}^{-1} )

Option: 1

249\: \mathrm{J}


Option: 2

415\: \mathrm{J}


Option: 3

498\: \mathrm{J}


Option: 4

830\: \mathrm{J}


Answers (1)

best_answer

Since Isochoric process,

\begin{aligned} \mathrm{\Delta Q =n C_{V} \Delta T} \\ \end{aligned}

         C_V=\frac{f}{2}R

Helium is monoatomic gas.

Degree of freedom (f)= 3

44.8 litre at STP = 2 mole

\mathrm{\Delta Q=2\times \frac{3R}{2}\times 20}

           \mathrm{=498\; J}

Correct answer is Option (3)

Posted by

Pankaj

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