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A cylinder of mass M and density d1 hanging from a string is lowered into a vessel of cross-sectional area A, containing a liquid of density d2 (d2>d1) until it is fully immersed. The increase in pressure at the bottom of the vessel is:

Option: 1

\frac{md2g}{d1A}


Option: 2

\frac{mg}{A}


Option: 3

\frac{md1g}{d2A}


Option: 4

Zero


Answers (1)

best_answer

Increase in pressure = Force exerted by the cylinder on the liquid / A

                                = \frac{vd2g}{A}

                                = \frac{md2g}{d1A}

Posted by

sudhir.kumar

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