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  • A cylindrical tube of uniform cross-sectional area is fitted with two air tight frictionless pistons.

A cylindrical tube of uniform cross-sectional area \mathrm{A} is fitted with two air tight frictionless pistons. The piston are connected to each other by a metallic wire. Initially, the pressure of the gas is \mathrm{p_{0}} and temperature is \mathrm{T_{0}}, atmospheric pressure is also \mathrm{p_{0}}.Now, the temperature of the gas is increased to \mathrm{2 T_{0}}, the tension of the wire will be

Option: 1

\mathrm{2 p_{0} A}


Option: 2

\mathrm{p_{0} A}


Option: 3

\mathrm{\frac{p_{0} A}{2}}


Option: 4

\mathrm{4 p_{0} A}


Answers (1)

best_answer

Volume of the gas is constant i.e. \mathrm{V= constant}
\mathrm{\therefore p \propto T}

i.e. pressure will be doubled temperature is doubled
\mathrm{\therefore \quad p=2 p_{0}}

Let \mathrm{F} be the tension in the wire. Then, equilibrium of any one piston gives
\mathrm{F =\left(p-p_0\right) A }
\mathrm{ =\left(2 p_0-p_0\right) A=p_0 {A}}

Posted by

Rakesh

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