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A cylindrical tube, open at both ends, has a fundamental frequency, f, in air. The tube is dipped vertically in water so that half of it is in water. The fundamental frequency of the air-column is now

Option: 1

f


Option: 2

\frac{f}{2}


Option: 3

\frac{3f}{4}


Option: 4

2f


Answers (1)

best_answer

:    When the tube of length l is open at both ends

\therefore f= \frac{\nu }{2l}\cdots \cdots (i)

where \nu is the speed of sound in air.

When the tube is dipped vertically in water and half of it is in water, it behaves closed

pipe \: \: length\: \: \frac{l}{{2}'}

\therefore \: \: {f}'= \frac{\nu }{4\left ( \frac{1}{2} \right )}= \frac{\nu }{2l}= f\: \: \cdots \cdots using (i)

Posted by

Kuldeep Maurya

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