Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A deuteron and a proton moving with equal kinetic energy enter into to a uniform magnetic field at right angle to the field. If <img alt="\mathrm{r_{d}}" src="https://entrancecorner.oncodecogs.com/

A deuteron and a proton moving with equal kinetic energy enter into to a uniform magnetic field at right angle to the field. If \mathrm{r_{d}}  and \mathrm{r_{p}} are the radii of their circular paths respectively, then the ratio \mathrm{\frac{r_{d}}{r_{p}}} will be \mathrm{\sqrt{x}: 1} where \mathrm{x} is ________.

Option: 1

2


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{r= \frac{mV}{qB}= \sqrt{\frac{2mK}{qB}}}
If kinetic energy is the same
\mathrm{r \propto \: \sqrt{\frac{m}{q}}}
\mathrm{\frac{r_{d}}{r_{p}}= \frac{\sqrt{\frac{m_{d}}{q_{d}}}}{\sqrt{\frac{m_{p}}{q_{p}}}}= \sqrt{\frac{m_{d}}{m_{p}}}\times \sqrt{\frac{q_{p}}{q_{d}}} }
       \mathrm{= \sqrt{\frac{2}{1}}\times \sqrt{\frac{1}{1}}= \sqrt{2}:1 }

Ans : (2)

Posted by

Pankaj Sanodiya

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

AESL expands Aakash Digital 2.0 to offer AI-powered coaching for NEET, JEE, Olympiads
anam-khan

Bihar Board extends BSEB Super 50 free coaching application last date to March 26
anam-khan

JEE Main City Intimation Slip 2025 Live: NTA session 2 exam city slips soon at jeemain.nta.nic.in

Latest Question