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A dilute solution for sulphuric acid is electrolysed using current of 0.3A for 2 hours to produce hydrogen and oxygen gas. The total volume of gases produced at STP in \mathrm{cm}^3 { Giver that : F = 96500 \mathrm{Cmol}^{-1} at STP, molar Volume of ideal gas is 22.7 \mathrm{~Lmol}^{-1}.

Option: 1

250 mL


Option: 2

382 mL


Option: 3

300 mL


Option: 4

262 mL


Answers (1)

best_answer

At Anode:-
2 \mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{O}_2(\mathrm{~g})+4 \mathrm{H}^{+}+4 e^{-}

At Cathode:-
2 \mathrm{H}^{+}+2 e^{-} \rightarrow \mathrm{H}_2(\mathrm{~g})

\mathrm{ \text { Now; No of gm~eq }=\frac{i \times t}{96500} }

\mathrm{ = \frac{0.3 \times 2 \times 60 \times 60}{96500} }

\mathrm{ =0.0223 }

\mathrm{ V_{\mathrm{O}_2}=\frac{0.0223}{4} \times 22.7=0.126 \\ }

\mathrm{ V_{\mathrm{H}_2}=\frac{0.0223}{2} \times 22.7=0.253 }

\mathrm{ V_{\text {total }} \approx 382 \mathrm{ml} \text { or cc }}

Posted by

Ritika Kankaria

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