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  • A dilute solution of sulphuric acid is electrolysed using a current of 0.10 A for 2 hours to produce hydrogen and oxygen gas. The total volume of gases produced at STP is ___________<img alt="\math

A dilute solution of sulphuric acid is electrolysed using a current of 0.10 A for 2 hours to produce hydrogen and oxygen gas. The total volume of gases produced at STP is ___________\mathrm{cm}^{3}. ( Nearest integer)

\text { [Given: Faraday constant } \mathrm{F}=96500\; \mathrm{C} \mathrm{mol}^{-1} \text { at } \mathrm{STP},\text {, molar volume of an ideal gas is }\text {22.7} \left. \mathrm{L} \; \mathrm{mol}^{-1}\right]

Option: 1

127


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{C}: 2 \mathrm{H}^{+}+2 e^{-} \rightarrow \mathrm{H}_{2} \\

\mathrm{~A}: \mathrm{H}_{2} \mathrm{O} \rightarrow \frac{1}{2} \mathrm{O}_{2}+2 \mathrm{H}^{+}+2 e^{-}

\therefore For every 2 mole of  \mathrm{e^{-}}, 1 mole of  \mathrm{H_{2}} and 0.5 mole of  \mathrm{O_{2}} are liberated.

\therefore 1 mole \mathrm{e^{-}} liberates 0.75 mole of gases

Now,

Charge passed =0.1 \times 2 \times 60 \times 60 \\

                      =720 \mathrm{~C}

\mathrm{\therefore \text { moles of electron }=\frac{720}{96500}=7.46 \times 10^{-3}}

\mathrm{ \therefore \text { volume of gases } =22.7 \times 0.75 \times 7.46 \times 10^{-3} }\\

                                       \mathrm{=0.127 \text { L}}

                                       \mathrm{=127cm^{3} }

Hence answer is 127

Posted by

jitender.kumar

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