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A disc is rolling without slipping on a surface. The radius of the disc is R. At t = 0, the top most point on the disc is A as shown in figure. When the disc completes half of its rotation, the displacement of point A from its initial position is

Option: 1

2 \mathrm{R} \sqrt{\left(1+4 \pi^2\right)}


Option: 2

\mathrm{R} \sqrt{\left(\pi^2+4\right)}


Option: 3

\text{2R}


Option: 4

\mathrm{R} \sqrt{\left(\pi^2+1\right)}


Answers (1)

best_answer

\text { Displacement }=\mathrm{A}^{\prime} \mathrm{A}

\begin{aligned} & \mathrm{A}^{\prime} \mathrm{A}=\sqrt{(\pi \mathrm{R})^2+(2 \mathrm{R})^2} \\ & \mathrm{~A}^{\prime} \mathrm{A}=\mathrm{R} \sqrt{\pi^2+4} \end{aligned}

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Divya Prakash Singh

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