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  • A disc with a flat small bottm beaker placed on it at a distance R from its center is revolving about an axis passing through the center and perpendicular to its plane with an angular velocity <img

A disc with a flat small bottm beaker placed on it at a distance R from its center is revolving about an axis passing through the center and perpendicular to its plane with an angular velocity \mathrm{\omega}. The coefficient of static friction between the bottom of the beaker and the surface of the disc is \mathrm{\mu}. The beaker will revolve with the disc if:

Option: 1

\mathrm{R\leq \frac{\mu g}{2\omega^{2}}}


Option: 2

\mathrm{R\leq \frac{\mu g}{\omega^{2}}}


Option: 3

\mathrm{R\geq \frac{\mu g}{2\omega^{2}}}


Option: 4

\mathrm{R\geq \frac{\mu g}{\omega^{2}}}


Answers (1)

best_answer

The beaker will revolve with the disc if friction force is able to provide necessary centripetal force 

\mathrm{f \leq \mu m g}\\                  

\mathrm{\frac{m v^{2}}{R}=m R \omega^{2} \leqslant \mu m g}\\

\mathrm{R \leqslant \frac{\mu g}{\omega^{2}}}

The correct option is (2)

Posted by

shivangi.bhatnagar

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