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A fair coin is tossed 10 times. What is the probability that ONLY the first two tosses will yield heads?

 

Option: 1

\left(\frac{1}{2}\right)^2


Option: 2

\mathrm{{ }^{10} C_2\left(\frac{1}{2}\right)^2}


Option: 3

\mathrm{\left(\frac{1}{2}\right)^{10}}


Option: 4

\mathrm{{ }^{10} C_2\left(\frac{1}{2}\right)^{10}}


Answers (1)

best_answer

P (Only the first two tosses yield heads)

                          \mathrm{=P(H, H, T, T, \ldots, T)}

Each toss is independent

\therefore Required Probability

                                 \mathrm{=P(H) P(H) P(T) P(T) \ldots P(T)}

                                 =\left(\frac{1}{2}\right)^2\left(\frac{1}{2}\right)^8=\left(\frac{1}{2}\right)^{10}

Posted by

Nehul

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