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  • A first order reaction has a rate constant, <img alt="\mathrm k=5.5 \times 10^{-14} \mathrm{s}^{-1}" src="http://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%20k%3D5.5%20%5Ctimes%2010%5E%

A first order reaction has a rate constant, \mathrm k=5.5 \times 10^{-14} \mathrm{s}^{-1}, calculate the Half life of reaction?

Option: 1

1.26 \times 10^{13} \mathrm{\: s}


Option: 2

0.693 \times 10^{14} \mathrm{\: s}


Option: 3

6.93\times 10^{14} \mathrm{\: s}


Option: 4

12.6 \times 10^{14} \mathrm{\: s}


Answers (1)

best_answer

As we have learnt,

Half life for a first order reaction is given as:

\mathrm{t_{1 / 2}=\frac{0.693}{k}=\frac{0.693}{5.5 \times 10^{-14} \mathrm{s}^{-1}}=1.26 \times 10^{13} \mathrm{\: s}}

Therefore, option(1) is correct

Posted by

vinayak

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