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  • A first order reaction has a specific reaction rate of  <img alt="\mathrm{0.3 \times10^{-3} s^{-1}}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B0.3%20%5Ctimes10%5E%7

A first order reaction has a specific reaction rate of  \mathrm{0.3 \times10^{-3} s^{-1}}. How much time will it take for 20 g of the reactant to reduce to 10 g? 

 

Option: 1

2310 second 


Option: 2

693 second 


Option: 3

231 second 


Option: 4

None of the above


Answers (1)

best_answer

For a first orer reaction, half-time \mathrm{t_{3 / 2}}  is given as

\mathrm{t_{3 / 2}= 0.693 / \mathrm{K} } where \mathrm{ \mathrm{K} }   is rate constant 
\mathrm{ \Rightarrow t_{3 / 2}=0.693 /\left(0.3 \times 10^{-3} \mathrm{~s}^{-1}\right) \\ }
\mathrm{ \Rightarrow t_{3 / 2}=2310 \mathrm{~s}}

For reduction of reactant concentration from \mathrm{ 40 \mathrm{~g}}  to  \mathrm{ 10 \mathrm{~g}} it shall take 2 half-times.
So time taken \mathrm{ =2 \times 693 \mathrm{~s}=1386 \mathrm{~s}}

Posted by

Irshad Anwar

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