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A FM Broad cast transmitter, using modulating signal of frequency 20 \mathrm{kHz} has a deviation ratio of 10 . The Bandwidth required for transmission is:
 

Option: 1

220 \mathrm{kHz}


Option: 2

180 \mathrm{kHz}


Option: 3

360 \mathrm{kHz}


Option: 4

440 \mathrm{kHz}


Answers (1)

best_answer

\mathrm{Deviation \: Ratio =\frac{Maximum \: frequency\: deviation}{Maximum \: modulating \: signal}}

\mathrm{10 =\frac{\Delta f_m}{f_m}=\frac{\Delta f_m}{20} }

\mathrm{\Delta f_m =200 \mathrm{kHz} }

\mathrm{\text { Bandwidth } =2\left(\Delta f_m+f_m\right) }

                        \mathrm{=2(200+20) }

                        \mathrm{=440 \mathrm{kHz}}

Hence 4 is correct option

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