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  • A force acts for 20 s on a body of mass 20 kg, starting from rest, after which the force ceases and then body describes 50 m in the next 10 s. The value of force will be:<div class='qna-option'

A force acts for 20 s on a body of mass 20 kg, starting from rest, after which the force ceases and then body describes 50 m in the next 10 s. The value of force will be:

Option: 1

40 \mathrm{~N}


Option: 2

5 \mathrm{~N}


Option: 3

20 \mathrm{~N}


Option: 4

10 \mathrm{~N}


Answers (1)

best_answer

\begin{aligned} & 50=\mathrm{V} \times 10 \\ & \mathrm{~V}=5 \mathrm{~ms}^{-1} \\ & \mathrm{~V}=0+\mathrm{a} \times 20 \\ & 5=\mathrm{a} \times 20 \\ & \mathrm{a}=\frac{1}{4} \mathrm{~ms}^{-2} \\ & \mathrm{~F}=\mathrm{ma}=20 \times \frac{1}{4}=5 \mathrm{~N} \end{aligned}

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sudhir.kumar

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