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  • A force of  acts on a charged particle placed between two plates of a charged capacitors. If

A force of \mathrm{10N} acts on a charged particle placed between two plates of a charged capacitors. If one plate of capacitor is removed, the the force acting o that particle will be: 

Option: 1

\mathrm{5N}


Option: 2

\mathrm{10N}


Option: 3

\mathrm{20N}


Option: 4

\mathrm{Zero}


Answers (1)

best_answer

\mathrm{\text {F}_{inital} =q \times E} \\

\mathrm{=q \times \frac{\sigma}{\varepsilon_{0}}=10 \mathrm{~N}}

\mathrm{\sigma\rightarrow } Surface charge density

If one plate is removed

 

\mathrm{F =q E'} \\

\mathrm{=q_{1} \times \frac{\sigma}{2 \varepsilon_{0}}=5 \mathrm{~N}}

Hence the correct answer is option 1.

Posted by

vishal kumar

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