Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

A function f is defined on [-3, 3] as
f(x)=\left\{\begin{matrix} min {\left | x \right |, 2-x^2} & -2 \leq x\leq 2\\ [\left | x \right |]& , 2<\left | x \right | \leq 3 \end{matrix}\right.
where [x] denotes the greatest integer \leq x. The number of points, where f is not differentiable in (-3, 3) is ______.
Option: 1 3
Option: 2 5
Option: 3 2
Option: 4 1

Answers (1)

best_answer

f(x)=\left\{\begin{array}{rlr} \min \left\{|x|, 2-x^{2}\right\} & , & -2 \leq x \leq 2 \\ {[|x|]} & , & 2<|x| \leq 3 \end{array}\right.

\Rightarrow \mathrm{x} \in[-3,-2) \cup(2,3]

plot the graph

The number of point of non-differentiability in (-3, 3) is 5

Posted by

himanshu.meshram

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024 session 2 result date announced; Steps to check NTA session 2 scores
anam-khan

JEE Main 2024 session 2 final answer key soon at jeemain.nta.ac.in; result on April 25
anam-khan

JEE Main 2024 Session 2: Last day to challenge answer key today

Latest Question