Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A galvanometer of resistance , shunted by a resistance of <img alt="50 \, \mathrm{ohm}" src="/latex-image/?50%20%5C%2C%20%5Cmathrm%7Bohm%7D"

A galvanometer of resistance 95 \Omega, shunted by a resistance of 50 \, \mathrm{ohm} gives a deflection of 50 divisions when joined in series with a resistance of 20 \, \mathrm{k} \Omega and a 2 volt accumulator, The current sensitivity of galvanometer (in \operatorname{div}/\mu \mathrm{A}) is 

Option: 1

0.25 \operatorname{div} / \mu \mathrm{A}


Option: 2

0.50 \operatorname{div} /\mu \mathrm{A}


Option: 3

1 \operatorname{div} / \mu \mathrm{A}


Option: 4

2 \operatorname{div} / \mu \mathrm{A}


Answers (1)

best_answer

Current in the circuit

\mathrm{I=\frac{2}{20 \times 10^{3}}=10^{-4} \mathrm{~A}}
\mathrm{=100 \mu \mathrm{A}}

This current produces deflection of 50 div in the galvanometer
\mathrm{\mathrm{CS}=\frac{\mathrm{Q}}{\mathrm{l}}=\frac{50 \mathrm{Div}}{100 \mu \mathrm{A}}=\frac{1 \text { Div }}{2 \mu \mathrm{A}}}
\mathrm{=0.50\, \mathrm{div} / \mu \mathrm{A}}

Posted by

Anam Khan

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 Registration Live: NTA session 1 application last date today; official website, syllabus
anam-khan

JEE Main 2025 session 1 registration ends today at jeemain.nta.nic.in; application correction from November 26
anam-khan

JEE Main 2025 registration ends tomorrow; changes introduced in exam this year

Latest Question