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A gas undergoes change from state A to state B.  In this process, the heat absorbed and work done by the gas is 5 J and 8 J, respectively.  Now gas is brought back to A by another process during which 3 J of heat is evolved.  In this reverse process of B to A :
Option: 1  10 J of the work will be done by the gas.
Option: 2  6 J of the work will be done by the gas.
Option: 3 10 J of the work will be done by the surrounding on gas.
Option: 4  6 J of the work will be done by the surrounding on gas.  
 

Answers (1)

best_answer

A \longrightarrow B

\mathrm{Q=5 \ J}

\mathrm{W=8\ J}

\mathrm{\Delta U_{AB}=Q+W=5+(-8)=-3J}

 

B \longrightarrow A

\mathrm{Q=-3J}

\mathrm{\Delta U_{BA}=3J}

\Delta U_{BA}=-3+W

3+3=W

W=6J

(work is done on the system)

Or

As work done has a positive sign, work is done by the surrounding on the gas.

Hence, the correct answer is (4)

Posted by

vishal kumar

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