# A gas undergoes change from state A to state B.  In this process, the heat absorbed and work done by the gas is 5 J and 8 J, respectively.  Now gas is brought back to A by another process during which 3 J of heat is evolved.  In this reverse process of B to A : Option: 1  10 J of the work will be done by the gas. Option: 2  6 J of the work will be done by the gas. Option: 3 10 J of the work will be done by the surrounding on gas. Option: 4  6 J of the work will be done by the surrounding on gas.

$A \longrightarrow B$

$\mathrm{Q=5 \ J}$

$\mathrm{W=8\ J}$

$\mathrm{\Delta U_{AB}=Q+W=5+(-8)=-3J}$

$B \longrightarrow A$

$\mathrm{Q=-3J}$

$\mathrm{\Delta U_{BA}=3J}$

$\Delta U_{BA}=-3+W$

$3+3=W$

$W=6J$

(work is done on the system)

Or

As work done has a positive sign, work is done by the surrounding on the gas.

Hence, the correct answer is (4)

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