A given metal crystallizes out with BCC structure having an edge length of 3.464 A^{\circ} , what will be the radius of one atom?

Answers (1)

For BCC structure,         

                              r=\frac{a\sqrt{3}}{4}

                             r=\frac{3.464\times 1.732}{4}=2A^{\circ}=200pm

The relation between the radius of the constituent particle, R and edge length, a for body-centered cubic unit cell -

Preparation Products

Knockout JEE Main Sept 2020

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 12999/- ₹ 6999/-
Buy Now
Rank Booster JEE Main 2020

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 9999/- ₹ 4999/-
Buy Now
Test Series JEE Main Sept 2020

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 4999/- ₹ 1999/-
Buy Now
Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Exams
Articles
Questions