A given metal crystallizes out with BCC structure having an edge length of 3.464 A^{\circ} , what will be the radius of one atom?

Answers (1)

For BCC structure,         

                              r=\frac{a\sqrt{3}}{4}

                             r=\frac{3.464\times 1.732}{4}=2A^{\circ}=200pm

The relation between the radius of the constituent particle, R and edge length, a for body-centered cubic unit cell -

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