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  • A glass slab is placed on a horizontal platform. A travelling microscope is used to measure the apparent shift of an object placed beneath the glass slab. The microscope is focused on the top surfa

A glass slab is placed on a horizontal platform. A travelling microscope is used to measure the apparent shift of an object placed beneath the glass slab. The microscope is focused on the top surface of the object without the glass slab. The measured apparent shift is 2.5 mm. The thickness of the glass slab is 5 mm. If the microscope’s least count is 0.01 mm, calculate the refractive index of the glass.

Option: 1

1.005


Option: 2

1.12


Option: 3

1.33


Option: 4

1.25


Answers (1)

best_answer

Given:

Apparent shift (d) = 2.5 mm
Thickness of glass slab (t) = 5 mm
Least count of the travelling microscope (LC) = 0.01 mm

The actual shift (D) can be calculated using the formula:

                    D = d * LC

                    D = 2.5 mm * 0.01 mm

                    D = 0.025 mm

The refractive index (n) of the glass slab can be calculated using the formula for the apparent shift:

                    n = \frac{D}{t} + 1

                    n = \frac{0.025 mm}{5 mm} + 1

Step 1: Calculate n:

                    n = 1.005

The refractive index of the glass slab is 1.005.

Posted by

Devendra Khairwa

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