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A H-atom moving with speed v makes a head on collision with a H-atom at rest. Both atoms are in ground state. The minimum value of velocity v for which one of the atom may excite is:\left(\mathrm{m}_{\mathrm{H}}=1.67 \times 10^{-27} \mathrm{~kg}\right) 

Option: 1

6.25 \times 10^4 \mathrm{~ms}^{-1}


Option: 2

8 \times 10^4 \mathrm{~ms}^{-1}


Option: 3

7.25 \times 10^4 \mathrm{~ms}^{-1}


Option: 4

13.6 \times 10^4 \mathrm{~ms}^{-1}


Answers (1)

best_answer

Minimum 10.2 eV energy is required to excite a hydrogen atom. In perfectly inelastic collision maximum energy is lost.

\therefore \quad \text { energy lost }=\frac{1}{2}(2 \mathrm{~m})\left(\frac{\mathrm{v}}{2}\right)^2=10.2 \times 1.6 \times 10^{-19}

              \frac{1}{4} \mathrm{mv}^2=1.632 \times 10^{-18}

\therefore \quad \text { velocity } \mathrm{v}=\sqrt{\frac{1.632 \times 4 \times 10^{-18}}{1.67 \times 10^{-27}}}=6.25 \times 10^4 \mathrm{~ms}^{-1}

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jitender.kumar

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