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A half ring of radius R has a charge of \lambda  per unit length. The electric potential at the centre of the half ring is-

Option: 1

\frac{k \lambda}{R}


Option: 2

k \pi \lambda


Option: 3

\frac{k \lambda}{\pi R}


Option: 4

\frac{k \pi R}{R}


Answers (1)

best_answer


           Potential        V=k \frac{q}{R} =k \times \frac{\pi R \times \text { lengeh }}{R} \\


                        =\frac{k \times \pi R \lambda}{R}=k \pi \lambda

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Kuldeep Maurya

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